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Write a bash script to count the frequency of each word in a text file called words.txt.

For the sake of simplicity, you can assume:

  • words.txtOnly lowercase letters and' ' 。
  • Each word consists of lowercase letters only.
  • Words are separated by one or more space characters.

Example:

Assume that the contents of words.txt are as follows:

the day is sunny the the
the sunny is is

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Your script should output (in descending order of word frequency) :

the 4
is 3
sunny 2
day 1

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Description:

  • Don’t worry about sorting words with the same frequency. Each word has a unique frequency.
  • You can use one lineUnix pipesTo achieve?

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Note a few key words: word frequency descending order, counting the number of occurrences of each word, using a command line.

Using xargs to display all rows in a single column:

cat words.txt | xargs -n1

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(2) usesort + uniqFunctions are arranged:

  • sort -nrSort values in descending order by size.
  • uniq -cDisplays the number of times a row has been repeated next to each column.
cat words.txt | xargs -n1 | sort | uniq -c | sort -nr

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(3) usingawk + printFunction () swap columns 1 and 2:

cat words.txt | xargs -n 1 | sort | uniq -c | sort -nr | awk '{print $2" "$1}'

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So far, the problem is solved.

Go to LeetCode and check out the results:

❄️ at the end ❄️

Xargs, sort, uniq, awk

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