Topic describes

Example 1 Enter: drop table if exists' employees'; CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL, `birth_date` date NOT NULL, `first_name` varchar(14) NOT NULL, `last_name` varchar(16) NOT NULL, `gender` char(1) NOT NULL, `hire_date` date NOT NULL, PRIMARY KEY (`emp_no`)); INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26'); INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21'); INSERT INTO employees VALUES(10003,'1959-12-03','Parto','Bamford','M','1986-08-28'); INSERT INTO employees VALUES(10004,'1954-05-01','Chirstian','Koblick','M','1986-12-01'); INSERT INTO employees VALUES(10005,'1955-01-21','Kyoichi','Maliniak','M','1989-09-12'); INSERT INTO employees VALUES(10006,'1953-04-20','Anneke','Preusig','F','1989-06-02'); INSERT INTO employees VALUES(10007,'1957-05-23','Tzvetan','Zielinski','F','1989-02-10'); INSERT INTO employees VALUES(10008,'1958-02-19','Saniya','Kalloufi','M','1994-09-15'); INSERT INTO employees VALUES(10009,'1952-04-19','Sumant','Peac','F','1985-02-18'); INSERT INTO employees VALUES(10010,'1963-06-01','Duangkaew','Piveteau','F','1989-08-24'); INSERT INTO employees VALUES(10011,'1953-11-07','Mary','Sluis','F','1990-01-22'); Copy the output: 10008 | | 1958-02-19 Saniya | Kalloufi | | M 1994-09-15Copy the code

Answer key

At first glance, the solution did pass the runtime: 15ms over 64.85% of Sqlite code footprint: 3324KB over 46.78% of Sqlite code footprint

SELECT * FROM employees ORDER BY hire_date DESC LIMIT 1;
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But this solution is actually incomplete. What if there are more than one newest employee at the same time?

SELECT MAX(hire_date) FROM employees, SELECT MAX(hire_date) FROM employees SELECT hire_date FROM employees WHERE hire_date IN (SELECT MAX(hire_date) FROM employees)

Elapsed time: 13ms over 77.91% Code submitted with Sqlite Memory: 3320KB Over 61.30% code submitted with Sqlite

SELECT * FROM employees 
WHERE hire_date IN (SELECT MAX(hire_date) FROM employees);
Copy the code