My JS algorithm to climb the pit - the square root of x

Address: leetcode-cn.com/problems/sq…

SQRT is not allowed to be used as a check-in method

var mySqrt = function(x) { for(let left = 0;; left++) { if(left**2 === x) { return left; } else if(left**2 > x) { return left - 1; }}};Copy the code

Execution time: 132 ms, beating 19.50% of all JavaScript commits

Memory consumption: 39.2 MB, beating 24.60% of all JavaScript commits

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