Original link: leetcode-cn.com/problems/tw…
Answer:
- The result is returned if the sum of two numbers is found to be target.
- Note that the second loop only iterates through the elements left after the first loop.
/** * @param {number[]} nums * @param {number} target * @return {number[]} */ var twoSum = function(nums, target) { for (let i = 0; i < nums.length - 1; I ++) {// iterate over the element after I for (let j = I + 1; j < nums.length; If (nums[I] + nums[j] === target) {return [I, j]; }}}};Copy the code