Converting from decimal to hexadecimal:
Integer.toHexString(int i)
Decimal to octal
Integer.toOctalString(int i)
Decimal to binary
Integer.toBinaryString(int i)
Conversion from hexadecimal to decimal
Integer.valueOf(“FFFF”,16).toString()
Octal is converted to decimal
Integer.valueOf(“876”,8).toString()
Binary to decimal
Integer.valueOf(“0101”,2).toString()
Is there any way to convert 2,8,16 to 10 directly?
Java. Lang. Integer class
parseInt(String s, int radix)
Parses a string argument to a signed integer, using the cardinality specified by the second argument.
examples from jdk:
parseInt(“0”, 10) returns 0
parseInt(“473”, 10) returns 473
parseInt(“-0”, 10) returns 0
parseInt(“-FF”, 16) returns -255
parseInt(“1100110”, 2) returns 102
parseInt(“2147483647”, 10) returns 2147483647
parseInt(“-2147483648”, 10) returns -2147483648
parseInt(“2147483648”, 10) throws a NumberFormatException
parseInt(“99”,
parseInt(“Kona”, 10) throws a NumberFormatException
parseInt(“Kona”, 27) returns 411787
How to write base conversion (two, eight, sixteen) without algorithm
Integer.toBinaryString
Integer.toOctalString
Integer.toHexString
Example 2
public class Test{
public static void main(String args[]){
int i=100;
String binStr=Integer.toBinaryString(i);
String otcStr=Integer.toOctalString(i);
String hexStr=Integer.toHexString(i);
System.out.println(binStr);
}
Example 2
public class TestStringFormat {
public static void main(String[] args) {
if (args.length == 0) {
System.out.println(“usage: java TestStringFormat <a number>”);
System.exit(0);
}
Integer factor = Integer.valueOf(args[0]);
String s;
s = String.format(“%d”, factor);
System.out.println(s);
s = String.format(“%x”, factor);
System.out.println(s);
s = String.format(“%o”, factor);
System.out.println(s);
}
}
Other methods:
Integer.tohexstring (your decimal number);
For example,
String temp = Integer.toHexString(75);
The output temp is 4b
// Enter a decimal number and convert it to hexadecimal
import java.io.*;
public class toHex{
public static void main(String[]args){
int input; // Store the input data
// Create an instance of the input string
BufferedReader strin=new BufferedReader(new InputStreamReader(System.in));
System.out.println(” Please enter an integer: “);
String x=null;
try{
x=strin.readLine();
}catch(IOException ex){
ex.printStackTrace();
}
input=Integer.parseInt(x);
System.out.println (” The number you entered is: “+input); // Outputs the number received from the keyboard
System.out.println (” Its hexadecimal is: “+ integer.tohexString (input)); // Convert base 10 to base 16 with toHexString
}
}