Chainable if
!
Akua
is a very useful tools! It can solve your nested if-tree
, make it become chainable if
!
Akua
can help you code maintainable if!
Install
npm install akua --save
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Use
normal nested if-tree
let normalIf = ''; const normailIfStart = new Date().getTime(); if (conditionA) { const tempA = 'tempA'; normalIf += 'a'; if (conditionB) { normalIf += 'b'; normalIf += tempA; if (conditionC) { normalIf += 'c'; if (conditionD) { normalIf += 'd'; if (conditionE) { normalIf += 'e'; } } } } else { normalIf += '! b'; } if (conditionF) { normalIf += 'f'; if (conditionG) { normalIf += 'g'; } } } else { normalIf += '! a'; }Copy the code
akua if
let akuaIf = ''; const ifTree = new akua(); ifTree .inject(conditionA, 'a', (obj) => { obj.tempA = 'tempA'; akuaIf += 'a'; }) .inject(! conditionA, '! a', () => { akuaIf += '! a'; }) .inject(conditionB, 'a->b', (obj) => { akuaIf += 'b'; akuaIf += obj.tempA; }) .inject(! conditionB, 'a->! b', () => { akuaIf += '! b'; }) .inject(conditionC, 'b->c', () => { akuaIf += 'c'; }) .inject(conditionD, 'c->d', () => { akuaIf += 'd'; }) .inject(conditionE, 'd->e', () => { akuaIf += 'e'; }) .inject(conditionF, 'a->f', () => { akuaIf += 'f'; }) .inject(conditionG, 'f->g', () => { akuaIf += 'g'; }) .parse();Copy the code
Finally, normalIf === akuaIf, you can git clone this project and NPM run test if you doubt!
Unit Test Exampls
Perfomance
npm run test
Test: 1000, SUCCESS: 1000, fail: 0 normal-if cost time: 2ms Akua-if cost time: 7ms
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Test: 100000, success: 100000, fail: 0 normal-if cost time: 19ms akua-if cost time: 175ms
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