C Language programming introduction Training (2)

The article directories

• C Language programming introduction Training (2)
• • Exercise 11: ASCII code
  • Exercise 12: Date of birth input and output
  • Exercise 13: Format input and swap output
  • Exercise 14: Convert characters to ASCII values
  • Exercise 15: Evaluate expressions
  • Exercise 16: Calculating residual division
  • Exercise 17: Kiki counts
  • Exercise 18: The ones digit of a floating point number
  • Exercise 19: How many seconds can you Live?
  • Exercise 20: Time shift
  • Exercise 21: Total score and even score calculation
  • Exercise 22: Calculate your body mass index
  • Exercise 23: Calculate the perimeter and area of a triangle
  • Exercise 24: Calculate the volume of a sphere
  • Exercise 25: Case conversion
  • Exercise 26: Two to the NTH power
• To be continued…….

Exercise 11: ASCII code

Topic describes

BoBo taught KiKi that characters represented by character constants or character variables are stored in memory as ASCII codes. BoBo has a problem for KiKi, convert the following ASCII characters into corresponding characters and output them.

73, 32, 99, 97, 110, 32, 100, 111, 32, 105, 116, 33

Input description:

There is no

Output description:

Convert all ASCII characters given in the output question to the corresponding characters.

The code is as follows:

#include  <stdio.h>

int main(a)
{
	char arr[12] = { 73.32.99.97.110.32.100.111.32.105.116.33 };
	int sz=sizeof(arr)/sizeof(arr[0]);
    int i = 0;
	for (i = 0; i<12; i++)
	{
		printf("%c", arr[i]);
	}
	return 0;
}
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Exercise 12: Date of birth input and output

#include <stdio.h>

int main(a)
{
    int year=0;
    int month=0;
    int day=0;
    
    scanf("%4d%2d%2d",&year,&month,&day);
    printf("year=%4d\n",year);
    printf("month=%02d\n",month);
    printf("date=%02d\n",day);
    return 0;
}
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Exercise 13: Format input and swap output

Topic describes

Enter two integers, ranging from -231 to 231-1, swap the two numbers and print the output.

Input description:

The input line consists of two integer ranges separated by commas (,).

Output description:

Print two integers in format separated by commas (,).

Example 1

The input

a=1,b=2

The output

a=2,b=1

The code is as follows:

#include <stdio.h>

int main(a)
{
    int a;
    int b;
    int tmp;
    scanf("a=%d,b=%d",&a,&b);
    tmp=a;
    a=b;
    b=tmp;
    printf("a=%d,b=%d",a,b);
    return 0;
}
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Remark:

If there are non-format characters in the format control string, this non-format character is also entered. \

Exercise 14: Convert characters to ASCII values

#include <stdio.h>

int main(a)
{
    char ch;
    scanf("%c",&ch);
        printf("%d",ch);
    return 0;
}
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Exercise 15: Evaluate expressions

Topic describes

Calculate the expression “(-8+22)× A-10 + C ÷2”, where a = 40, c = 212.

Input description:

No.

Output description:

(-8+22)× A-10 + C ÷2 after calculation, is an integer.

The code is as follows:

#include <stdio.h>
int main(a)
{
    int a=40;
    int c=212;
    int sum=0;
        sum=(- 8 -+22)*a- 10+c/2;
    printf("%d\n",sum);
    return 0;
}
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Exercise 16: Calculating residual division

#include <stdio.h>
int main(a)
{
    int a=0;
    int b=0;
    scanf("%d %d",&a,&b);
    printf("%d %d",a/b,a%b);
    return 0;
}
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Exercise 17: Kiki counts

Topic describes

Problem: KiKi is 5 years old and can already recognize and add non-negative integers up to 100. However, Mr BoBo noticed that KiKi’s rules for calculating positive integers greater than or equal to 100 were as follows:

1. Keep only the last two digits of the number, for example: for KiKi 1234 is equivalent to 34;
2. If the result is greater than or equal to 100, KIKI also keeps only the last two digits of the result, and only the ones digits if the tens place is 0.

For example, 45+80 = 25 requires that non-negative integers A and b be given, and the KiKi algorithm is simulated to calculate the value of a+b.

Input description:

On one line, enter two non-negative integers, a and b, separated by a space. (0 <= a,b<= 231-1).

Output description:

For each set of inputs, the output calculates the value of a+b according to KiKi’s algorithm.

Example 1

The input

45, 80

The output

25

The code is as follows:

#include <stdio.h>

int main(a)
{
    int a;
    int b;
    scanf("%d %d",&a,&b);
    printf("%d\n",(a%100+b%100) %100);
    //printf("%d",(a+b)%100);
    
    return 0;
}
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Exercise 18: The ones digit of a floating point number

#include <stdio.h>
int main(a)
{
    float c;
    scanf("%f",&c);
    printf("%d", (int)c%10);
    return 0;
}
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Exercise 19: How many seconds can you Live?

Topic describes

Question: there are about 3.156×107s in a year, ask to input your age, show how many seconds of this age.

Input description:

A line that includes an integer age(0<age<=200).

Output description:

A line containing an integer that outputs the number of seconds corresponding to the age.

Example 1 Input

20

The output

631200000

The code is as follows:

#include <stdio.h>
int main(a)
{
	int age=0;
	scanf("%d", &age);
	long long ret = age*3.156 e7;
		printf("%lld", ret);

	return 0;
}
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Note: the exponential form of C language should be noted, and the size of the data value of int is limited. For large numbers, we should have long or long long stores.

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Exercise 20: Time shift

#include <stdio.h>

int main(a)
{
    int sec=0;
    scanf("%d",&sec);
    printf("%d %d %d",sec/60/60,sec/60%60,sec%60);
    return 0;
}
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Exercise 21: Total score and even score calculation

Topic describes

Input a student’s 3 subject scores in turn, output the student’s total score and average score on the screen.

Input description:

One line, three subject scores separated by a space.

Output description:

A line, total grade and average grade (two decimal places reserved), separated by a space.

Example 1

The input

79.5 80.0 98.0

The output

257.50 85.83

The code is as follows:

#include <stdio.h>
int main(a)
{
    float a,b,c;
    scanf("%f %f %f",&a,&b,&c);
    printf("%.2f %.2f",a+b+c,(a+b+c)/3.0);
    return 0;
}
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Exercise 22: Calculate your body mass index

#include <stdio.h>
#include<math.h>
int main(a)
{
    int wei,high;
    scanf("%d %d",&wei,&high);
   printf("%.2f",wei/(pow((high/100.0),2)));
    return 0;
}
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Exercise 23: Calculate the perimeter and area of a triangle

Topic describes

Calculate the perimeter and area of the triangle according to the given three sides a, B and C (0 < a, b, c < 100,000).

Input description:

A line of three sides of a triangle separated by a space.

Output description:

A line containing the perimeter and area of a triangle (two decimal digits reserved) separated by a space. For details about the output format, see the output example.

Example 1

The input

3 3 3

The output

Circumference area = 9.00 = 3.90

The code is as follows:

#include <stdio.h>
#include <math.h>
int main(a)
{
	int a = 0;
	int b = 0;
	int c = 0;
	scanf("%d%d%d", &a, &b, &c);
	double circumference = a + b + c;
	float p = (a + b + c) / 2.0;
	float area = sqrt(p*(p - a)*(p - b)*(p - c));
		
		printf("circumference=%.2f area=%.2f", circumference, area);

		return 0;
}
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Note: familiar with the application of square function, and Helen’s formula to calculate the area of a triangle.

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Exercise 24: Calculate the volume of a sphere

#include  <stdio.h>
#include  <math.h>
int main(a)
{
    double r=0.0;
    double pi=3.1415926;
    scanf("%lf",&r);
    printf("%.3lf".4.0/3*pi*r*r*r);
    return 0;
}
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Exercise 25: Case conversion

Topic describes

The realization of letter case conversion. Multiple input/output groups.

Input description:

Multiple groups of inputs, each line in capital letters.

Output description:

Lowercase letters for each set of input and output.

Example 1 Input

A

B

The output

a

b

The code is as follows:

#include <stdio.h>
int main(a)
{
	char ch ;
	while((ch = getchar()) ! = EOF) { getchar();putchar(ch+32);

		printf("\n");
	}
	return 0;
}
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Note: When entering multiple groups, note that carriage return is also a letter, so “absorb” (getchar()) to remove the letter.

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Exercise 26: Two to the NTH power

#include <stdio.h>

int main(a)
{
    int n=0;
    while(scanf("%d",&n)! =EOF) {printf("%d\n".1<<n);
    }
    return 0;
}
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To be continued…