Python nested list sort, dictionary sort

temp_dict = {
    "axiaoming": 16."bxiaoli": 18."cxiaoxue": 19."dxiaolin": 20."fxiaojuan": 21."exiaolu": 17,
}

temp_list_test = [
    ('cxiaoxue'.19),
    ('exiaolu'.17),
    ('dxiaolin'.20),
    ('bxiaoli'.18),
    ('axiaoming'.18),
    ('fxiaojuan'.21)]if __name__ == "__main__": # sort a nested list (multidimensional array) print(f"temp_list_test before = {temp_list_test}")
    temp_list_test.sort(key=lambda x: (x[1], x[0], reverse=False) #1The second element is in the same order0Print (f"temp_list_test after = {temp_list_test}"If the dictionary is sorted by value, the output is a list, and each element in the list is a tuple, as follows:  temp_list = sorted(temp_dict.items(), key=lambda item: item[1], reverse=True) # print(f"temp_list = {temp_list}")

    temp_list = sorted(temp_dict.items(), key=lambda item: item[0], reverse=True) # print(f"temp_list = {temp_list}") 

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